Julain has 200ml of 35% hand sanatizer. Sarah has 150ml of 85% hand sanatizer. They mix the sanatizers together in an effort to acheive 60% concentration. 1) How many milliliters of pure alchol are in the new mixture? 2) How many mililliters of water are in the new mixture? 3)What is the concentration of alchol in the new mixture?(Round your answer to one decimal place)

210ml, 140 ml, 60%

Step-by-step explanation:

Given

Juli has 200 ml of 35% hand sanitizer

Sarah has 150 ml of 85% hand sanitizer

The mixture has 60% con. i.e. 60 % is Alcohol and 40 % water

The final volume of the mixture =200+150=350 ml

Now, 60% of 350 ml=

So, pure Alcohol is 210 ml

Water in the final mixture=

The concentration of Alcohol is 60%

step-by-step explanation:

i have done this all on a piece of paper but idk how to put it on here cuz it needs to be drawn

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15