Two butterflies simultaneously leave an aster flowerbed and fly to a rose flowerbed. One butterfly flies 10 m/min faster than the other, and so lands on a rose 1 minute earlier. Find the speed of each butterfly of the flower beds are 560m apart.

10.77 m/min ; 11.77 m/min

Step-by-step explanation:

Given :

Distance between the beds = 560m

Let :

Speed of butterfly 1 = x

Speed of butterfly 2 = x + 10

Time taken by butterfly one = t

Time taken by butterfly 2 = t - 1

Recall:

Speed = distance / time

Butterfly 1 :

x = 560 / t

xt = 560

t = 560/x

Butterfly 2:

x + 10 = 560 / t - 1

(x + 10)(t - 1) = 560

xt - x + 10t - 10 = 560

560 - x + 10(560/x) - 10 = 560

560 - x + 5600/x - 10 = 560

-x² - 560x + 6150 = 0

Using quadratic equation solver ;

x = - 570.77

x = 10.77

Speed can't be negative

Speed

butterfly 1= 10.77 m/min

Butterfly 2 = 10.77 +1 = 11.77 m /min

3: 2

step-by-step explanation:

shorter piece is 2: 3, so just reverse it, and you get 3: 2