The ages of 10 friends are consecutive integers. The sum of their ages is 710. they get together every Tuesday to play cards and enjoy each other's company calculate their ages

x = 66.5

x + 1 = 67.5

x + 2 = 68.5

x + 3 = 69.5

x + 4 = 70.5

x + 5 = 71.5

x + 6 = 72. 5

x + 7 = 73.5

x + 8 = 74.5

x + 9 = 84.5

Step-by-step explanation:

Given that :

Age of 10 friends are consecutive integers :

Let the ages be :

x, x+1, x+2, x+3, x+4, x+5, x+6, x+7, x+8, x+9

The sum of their ages = 710

Hence,

x + x+1 + x+2 + x+3 + x+4 + x+5 + x+6 + x+7 + x+8 + x+9 = 710

10x + 45 = 710

10x = 710 - 45

10x = 665

x = 665 / 10

x = 66.5

x + 1 = 67.5

x + 2 = 68.5

x + 3 = 69.5

x + 4 = 70.5

x + 5 = 71.5

x + 6 = 72. 5

x + 7 = 73.5

x + 8 = 74.5

x + 9 = 84.5

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.