Ten cards are numbered 10, 11, 12, ..., 19, one number per card. Brian removes three cards whose numbers are primes, and puts the remaining cards in a hat. If one card is then drawn at random from the hat, what is the probability that its number is a prime? A) 1/10
B) 1/9
C) 1/5
D) 2/5
E) None of The Above

None of the Above

Step-by-step explanation:

10 - Not Prime

11 - Prime

12 - Not Prime

13 - Prime

14 - Not Prime

15 - Not Prime

16 - Not Prime

17 - Prime

18 - Not Prime

19 - Prime

6 numbers NOT PRIME

4 numbers PRIME

4 - 3 = 1

1 + 6 = 7

1/7

y = 0.77(x)

step-by-step explanation:

the jacket retains this value after 23% cut or retains 77% of original value. plug original 87 jacket price for x and the remaining value should be y.

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]