What is the center of the circle with equation x^2 + y^2 - 10x +6y-2= 0

C(5, -3)

Step-by-step explanation:

Given the equation of circle;

x² + y² - 10x + 6y - 2 = 0

The general equation for a circle is given by the formula;

x² + y² + 2gx + 2fy + c = 0

Where the center is C(-g, -f)

To find the center, we would compare the two equations;

For the value of g.

2gx = -10x

2g = -10

g = -10/2

g = -5

To find the value of f.

2fy = 6y

2f = 6

f = 6/2

f = 3

Therefore, the center C(-g, -f) = (-(-5), -(3))

C(-g, -f) = C(5, -3).

step-by-step explanation:

idk the answer i want to say 10 but then it would be equal so try 9 but then yeah so yeah we love edgen