Jeremy wants to determine the number of solutions for the equation below without actually solving the equation. Negative 3 (x + 1) + 3 x = negative 3 (x minus 1) + 3 Which method should Jeremy use?

Options :

Determine whether the equation has the form a = a, and if it does, the equation has infinitely many solutions. Determine whether the equation has the form a = b, and if it does, the equation has no solution. Determine whether the equation has the form x = a, and if it does, the equation has one solution. Determine whether the equation has the form x = 0, and if it does, the equation has no solution.

Determine whether the equation has the form x = a

Step-by-step explanation:

Negative 3 (x + 1) + 3 x = negative 3 (x minus 1) + 3

-3(x + 1) + 3x = - 3(x - 1) + 3

If the equation has the form x =a, where a is the unknown and a is the value of the unknown 'x'

Expanding :

-3x - 3 + 3x = - 3x + 3 + 3

-3x + 3x -3 = - 3x + 6

-3 = - 3x + 6

-3 - 6 = - 3x

-9 = - 3x

x = 9/3

x = 3

b

step-by-step explanation:

the total is 23.97. 0.25% is off so you have to subtracting 25% from 100% and you will get 75% if you convert it to decimal you will get 0.75. you have to find the original because the formula is % times original = total.so you have the total and the % so you just have to plug it in.