A water tank is contaminated with a colony of 20 000 e. Coli bacteria. After 3 days the bacteria has grown to 28 284 e. Coli. What is the doubling time of the bacteria using an equation

6

Step-by-step explanation:

The formula for doubling time is given as:

P(t) = Po(2)^t/k

Where:

P(t) = Population after time t = 28,284

Po = Initial Population = 20,000

t = time = 3 days

k = doubling time = ?

28,284 = 20,000 × (2)^3/k

Divide both sides by 20,000

28,284/20,000 = 20,000/20,000 × (2)^3/k

1.4142 = (2)^3/k

2^1/2 = (2)^3/k

Divide both sides by 2

1/2 = 3/k

Cross Multiply

k × 1 = 2 × 3

k = 6

Therefore, the doubling time(k) of the bacteria is 6

ce pula mea vrei ma

step-by-step explanation:

gayule

answer: answer is c!

ok i got to organize the

3/15 and 12/55

3*

aha

3*4 equals 12 but not

a: no

b:

8/24 12/35

no

gautie

it's c

5/18 = 25/90

5*5=25

18*5 = 90

hope that you!

one more happy customer!

< 3

step-by-step explanation: