Find the unknown sides and angles of this triangle using the Law of Cosines. Round to the nearest hundredth.

Side c = 10.35

Angle A = 50.87°

Angle B = 94.13°

Step-by-step explanation:

The Law of Cosines states that:

a² = b² + c² - 2bcCos A

We are to to find side c, Angle A and B

side a = 14

sides b = 18

Angle C = 35°

1) Side c

= c² = a² + b² - 2abCos C

c² = 14² + 18² - 2 × 14 × 18 Cos 35

c = √(14² + 18² - 2 × 14 × 18 Cos 35)

c = 10.3512

Approximately = 10.35

2) Angle A

Cos A = b² + c² - a²/2bc

A = arc cos (b² + c² - a²/2bc)

A = arc cos (18² + 10.35² - 14²/2 × 18 × 10.35)

A = 50.8737°

A = Approximately = 50.87°

3) Angle B

Cos B = a² + c² - b²/2ac

B = arc cos (a² + c² - b²/2ac)

B = arc cos (14² + 10.35² - 18²/2 × 14× 10.35)

A = 94.13123°

A = Approximately = 94.13°

it should be a and d. lmk if i'm wrong xd

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b