What is the equation of the line perpendicular to 2x + y = -5 and passes through the point (4, -3)? Write your answer in slope-intercept form. Show all work.

2x+y= -5 is our equation and it passes through (4, -3)

point-slope formula= y-y1= m(x-x1)

fill in your formula, but flip the slope so its perpendicular. so slope is 1/2.

y+3=1/2(x-4) when i filled the formula in, i used 4 as x1 and -3 as y1.

y+3=1/2x-2 multiply x and -4 by 1/2

y=1/2x-5 subtract 3 from both sides.

Final y=1/2x-5

Also, i'm sorry my answer took so long the bell rang and so I had to leave this alone for a minute. Feel free to ask any questions :)

a

step-by-step explanation:

when a number is between two straight lines it means the absolute value.

to find absolute value you need to know how many numbers is that number away from 0.

when finding absolute value the number will always come out positive

so absolute value of -3 is 3

absolute value of 3/2 is 3/2

absolute value of -2 is 2

absolute value of 3.5 is 3.5

absolute value of -1 is 1

now put these numbers in order:

a)   |-1|, |3/2|, |-2|, |-3|, |3.5|