The height of a golf ball, in meters, x seconds after it has been hit is given by the expression -4.9x^(2) +4.8x+0.1 . When does the ball hit the ground?

t = 1 second

Step-by-step explanation:

The height of a golf ball, in meters, x seconds after it has been hit is given by the expression.

We need to find the time when the ball will hit the ground.

When it hits the ground, h=0

It is a quadratic equation. The solution of the above equation is :

x = 1 seconds, x = -0.02 seconds

Hence, after 1 second the ball will hit the ground.

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hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)