Mathematics, 25.01.2021 20:30 awkwardness92

Installation of a certain hardware takes a random amount of time with a standard deviation of 5 minutes. A computer technician installs this hardware on 64 different computers, with the average installation time of 42 minutes. Compute a 95% confidence interval for the mean installation time. Explain your interval in context.

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The 95% confidence interval for the mean installation time is (40.775, 43.225) and this can be determined by using the formula of margin of error.

Given :

Standard deviation is 5 minutes. Sample size is 64.Mean is 42 minutes.95% confidence interval.

The following steps can be used in order to determine the 95% confidence interval for the mean installation time:

Step 1 - The formula of margin of error can be used in order to determine the 95% confidence interval.

$M = z \times \dfrac{\sigma}{\sqrt{n} }$

where z is the z-score, $\sigma$ is the standard deviation, and the sample size is n.

Step 2 - Now, substitute the values of z, $\sigma$ , and n in the above formula.

$M = 1.96 \times \dfrac{5}{\sqrt{64} }$

M = 1.225

Step 3 - So, the 95% confidence interval is given by (M - $\mu$ , M + $\mu$ ) that is (40.775, 43.225).

The 95% confidence interval for the mean installation time is (40.775, 43.225).

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Answer from: kids2006

The 95% confidence interval for the mean installation time is between 40.775 minutes and 43.225 minutes. This means that for all instalations, in different computers, we are 95% sure that the mean time for installation will be in this interval.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of 1-0.025 = 0.975 , so z = 1.96

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 1.96*\frac{5}{\sqrt{64}} = 1.225$

The lower end of the interval is the sample mean subtracted by M. So it is 42 - 1.225 = 40.775 minutes

The upper end of the interval is the sample mean added to M. So it is 42 + 1.225 = 43.225 minutes

Answer from: Quest

y=x+9

step-by-step explanation:

Answer from: Quest

option: d is the correct answer.

d) none of the above.

step-by-step explanation:

clearly from the figure attached to the question we could see that there is no shape given. hence without any shape given in the figure and after rotation we can't obtained a square pyramid.

since, to obtain a image we need a proper figure of the pre-image so that it can be transformed.

hence, the correct answer is:

d) none of the above.

step-by-step explanation:

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Installation of a certain hardware takes a random amount of time with a standard deviation of 5 minu...