During a competition, an archer fires an arrow at a target on a hill. The arrow reaches a maximum
height of 127 feet 2.75 seconds after it was fired.
The arrow hits the target 5 seconds after the archer
releases it. If the arrow is released from a height of
6 feet, how far above the ground on which the
archer is standing is the target? Assume the
relationship between time and height is quadratic.

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step-by-step explanation:

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example 2 – simplify: step 1: completely factor both the numerators and denominators of all fractions. step 2: change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you need to multiply by the reciprocal. step 3 : cancel or reduce the fractions.