PLEASE HELP Consider the expressions (3m+2n−6) and (−4−6m+7n).

Part A

What is the sum of the expressions for n=−2 and m=5?

The sum is

5, -20

Step-by-step explanation:

Given the equation (3m+2n−6) and (−4−6m+7n).

Also, given that we're told that

n = -2 and

m = 5, if we take a rather direct approach by substituting like for like, we have

(3m+2n−6) = (3 * 5 + 2 * -2 - 6)

(3m+2n−6) = 15 - 4 - 6

(3m+2n−6) = 15 - 10

(3m+2n−6) = 5

(−4−6m+7n) = (-4 - 6 * 5 + 7 * 2)

(−4−6m+7n) = -4 - 30 + 14

(−4−6m+7n) = -34 + 14

(−4−6m+7n) = -20

Therefore, we proceed to conclude that the answers are 5 and -20 respectively

the range is 19

step-by-step explanation:

the range is biggest number minus the smallest, so in this case it would be

41 - 22 = 19

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3