A rectangle has a perimeter of 58. The width is 7 less than the length. Find the length and width of the rectangle.

Length = 18 Width = 11

Step-by-step explanation:

Perimeter = 2(length) + 2(width)

So let's label the unknown length as x. Width would then be (x-7). Then plug it into the perimeter equation.

2(x) + 2(x-7) = 58

Then use PEMDAS which will give us

2x+2x-14 = 58

Combine like terms

4x -14 = 58

Add 14 to both sides

4x = 72

To get x by itself you have to divide both sides by 4.

x = 18

So length is 18 and width is (18-7) which is 11.

practice. practice. practice.

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.