What is the surface area of a cuboid with sides measure 7 in, 3 in and 5 in?

The surface area the cuboid is 142 inches²

The surface area of the cuboid is given as:

= 2lw + 2lh + 2hw

where, l = length

h = height

w = width

Therefore, the surface area of the cuboid given will be:

= 2lw + 2lh + 2hw

= 2(7×3) + 2(7 × 5) + 2(3 × 5)

= 2(21) + 2(35) + 2(15)

= 42in + 70in + 30in

= 142 inches²

The surface area of the cuboid is 142inches²

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What is the surface area of a cuboid with sides measure 7 in, 3 in and 5 in?

Given,

> Sides = 7inches , 3inches, 5inches.

Now,

> Surface area of cuboid = 2lw + 2lh + 2hw

> 2 (7 × 3) + 2(7 × 5) + 2(3×5)

> 2 (21) + 2 (35) + 2 (15)

> 42 + 70 + 30

> 142 inches²

142 inches²

70.30

step-by-step explanation:

hi there!

question 1 answer: p/q can be terminating when q = 5^m * 2^n

question 2 answer: -1 and -1

question 3 answer: -4

question 4 answer: 5/12

hope this : )