What is a inelastic collision
IF YOU WANT BRAINLIEST DESCRIBE IT IN YOUR OWN WORD PLS

Kindly check explanation

Step-by-step explanation:

Think of inelastic Collison as a phenomenon whereby the colluding bodies do not rebound. That is the direction of motion of the two bodies after collision is in a single direction, moving with a single final velocity as opposed to bodies moving in different directions with differing final velocities after collision during an elastic collision. Therefore, the final kinetic energy during an inelastic Collison isn't conserved.

Mathematically,

Inelastic Collison can be written has :

m1u1 + m2u2 = v(m1 + m2)

Whereby ;

m1, m2 are masses of the first and second colliding objects

u1 and u2 are their initial velocities

Note that, we only have a single final velocity, v, which shows that the colliding objects move in the same direction after collision.

x = 23.78

step-by-step explanation:

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752