Your class hopes to collect at least 325 cans of food for the annual food drive. there were 135 cans donated the first week and 89 more the second week.
a. write an inequality that describes this situation. let c represent the number of cans of food that must be collected by the end of the third week for your class to meet or surpass its goal.
b. how many cans are needed to meet or surpass the goal?
can someone me figure out how to do this?

a) 135+89+C ≥ 325

b) C ≥ 101

Step-by-step explanation:

Given :

Class hopes to collect at least 325 cans of food for the annual food drive.

There were 135 cans donated in the first week

89 in the second week.

C represent the number of cans of food that must be collected by the end of the third week for your class to meet its goal

Solution :

a) first week = 135 cans

  second week = 89 cans

  third week  C cans must be collected

total cans should be atleast 325

So, inequality becomes : 135+89+C ≥ 325

b)

cans are needed to meet or surpass the goal C

⇒135+89+C ≥ 325

⇒C ≥ 325- 224

⇒C ≥ 101

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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answer: you need the equation in the question so i can answer it

step-by-step explanation: