8 Evaluate the expression below at x = 3, (31 – 5) = - 19 OA 710 OB. 585 OC 64 OD. 45 Reset Submit

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

c

step-by-step explanation:

the answer to this is:

factor 2x2+16x+24

2x2+16x+24

=2(x+2)(x+6)

answer:

2(x+2)(x+6)

hope this hmu if needed