The half-life of the element radon (Rn86) is 3.8 days. In a sample originally containing 1 gram of radon, the amount of left over days is given by the model () = (0.5)t/3.8 a) How much radon will be present after 7.6 days? b) How much radon will be present after 10 days?

a.0.25 g

b.0.16 g

Step-by-step explanation:

We are given that

Half-life of the element radon=3.8 days

Mass of sample of radon=1 g

The amount of radon left after t days is given by

a.

We have to find the amount of radon left after 7.6 days.

Substitute t=7.6 in the equation

Then, we get

Hence, the amount of radon will be present after 7.6 days=0.25 g

b. We have to find the amount of radon left after 10 days.

Substitute t=10 in the equation

Then, we get

Hence, the amount of radon will be present after 10 days=0.16 g

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right

the answer to this would be 5x^3-6x^2-24 over 3x^2

hope this if needed hmu