Do you know what the range is to y=3^x-2??

RANGE = (-2, infinity)

Step-by-step explanation:

Range: (−2,∞),{y|y>−2}

Step-by-step explanation:

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.

Interval Notation:

(−∞,∞)(-∞,∞)

Set-Builder Notation:

{x|x∈R}{x|x∈ℝ}

The range is the set of all valid yy values. Use the graph to find the range.

Interval Notation:

(−2,∞)(-2,∞)

Set-Builder Notation:

{y|y>−2}{y|y>-2}

Determine the domain and range.

Domain: (−∞,∞),{x|x∈R}(-∞,∞),{x|x∈ℝ}

Range: (−2,∞),{y|y>−2}(-2,∞),{y|y>-2}

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a

i believe that the answer is

b. y-1=-2(x-4)

hope this !