Help, please take your time to help a person in need lol please.

1. Slope: -2/3 y-int: 4

2. Slope: 3 y-int: 2

3. C,f,g,i

4. C

5. (10,15), (25,0), (0,25)

6. y=-x+25

7.

8. 2x+y=40

9. 2x+y>40

10.

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

3

step-by-step explanation: