Select the TWO systems of equations that have exactly one solution A. y= 3x + 1
y= -3x + 7

B. y= 3x + 1
y = x + 1

C. y= 3x + 1
y = 3x + 7

D. x + y = 10
2x + 2y = 20

E. x + y = 10
x + y = 12

D

Step-by-step explanation:

for D

let (x,y) = (5,5)

5+5=10

5+5=102×5+2×5=20

let (x,y) = (6,4)

6+4=10

6+4=102×6+2×4=20

168

step-by-step explanation:

i am pretty sure that the answer is 168

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right