Airlines A and B each operate one flight per day between the cities of Hartford and Chicago; the daily passenger volume between the two cities is 350. Because the quality of service and departure times for both airlines are similar, we assume that passengersselect the flights with equal probability and independently of one another. Required:
a. Let X denote the number of passengers on the flight operated by airline A. Describe the exact distribution of X; name it and identify the parameters.
b. If the plane for airline A carries 210 seats there is a positive probability that more than 210 passengers will turn up, in which case not all passengers can be accommodated. Estimate the probability of "overbooking"
c. Denote by n the minimum number of seats the aircraft should contain if it is desired that the probability of exceeding the seating capacity be less than 0.01. Find n

X ~ (350, 0.5)

0.00009

Step-by-step explanation:

Given that:

Daily passenger volume = 350

Since both airlines A and B have equal probability ;

p = 0.5

n = 350

X ~ (n, p)

X ~ (350, 0.5)

B.)

Mean, m= np = 350 * 0.5 = 175

Standard deviation, s = sqrt(np(1-p)) = sqrt(350*0.5*0.5) = sqrt(87.5)

Obtaining standardized score, Z

Z = (x - m) / s

x = 210

Z = (210 - 175) / sqrt(87.5)

Z = 35 / sqrt(87.5)

Z = 3.74

P(Z > 3.74) = 0.00009 (Z probability calculator)

answer: 414,377,008

step-by-step explanation:

just multiply it

la parábola es el lugar

geométrico en el cual los puntos tienen una distancia idéntica, equidistantes,

de un punto denominado foco, f, y una recta denominada directriz

el radio vector de una

parábola es el segmento que existe entre un punto cualquiera y el foco.

por la ecuación se observa

que la parábola abre hacia la derecha, por lo cual podemos usar las siguientes fórmulas

la ecuación ordinaria de la

parábola es y^2 = 4px, donde p es la longitud desde el vértice de la parábola al

foco.

la fórmula de la directriz

es x + p = 0

resolviendo:

y^2-9x = 0

y^2 = 9x

4p = 9, entonces p = 9/4

entonces el foco tendrá la

coordenada f(9/4,0)

la directriz vendrá

expresada por

x + p = 0

x = -p

x = -9/4

el problema indica que la

ordenada es igual a 6, entonces

(6)^2=9x

x = 36/9

x = 4

entonces el punto al cual

hay que obtener la distancia será p(4,6)

calculando se tendrá: pf = 

pf = 6,25 u

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step-by-step explanation: