An irregular polygon is shown below: Image of irregular polygon with length of 9 units and height of 4 units labeled on left side. Top side length of 4 units, the side adjacent to it on the right is 2 units. (Image below)

The area of the irregular polygon is _ square units.

numerical answers only, please!

answer: the common difference is -0.10

part a: 1.08

part b: 27.59

7.9m and 4.3°

step-by-step explanation:

let east be +x and north be +y, x = distance * cos θ, y = distance * sin θ  

for 3.5 south, y = -3.5  

for 8.2, x = 8.2 * cos 30 and y = 8.2 * sin 30  

for 15 west, x = -15  

total x = 8.2 * cos 30 – 15 ≈ -7.9  

total y = -3.5 + 8.2 * sin 30 = 0.6  

magnitude = [(8.2 * cos 30 – 15)^2 + 0.6^2)]^0.5  

the magnitude is approximately 7.9 m  

tan θ = y/x = 0.6/-7.9  

the angle is approximately 4.3˚ north of west