Andrew drives through 5 intersections with stop lights on his way to work. He records that he is stopped by a red light in 2 of the 5 intersections. If he uses this as his general probability of getting stopped at a red light on his way to or from work, how many times can he expect to be stopped at a red light over the next 40 times he drives through an intersection on his route? Andrew should expect to be stopped
times.

He should expect to be stopped a total of 16 times

Step-by-step explanation:

What the question is saying is that out of every 5 intersections, he would be stopped at 2.

Now, for forty times in which he passes through an intersection , we want to know the number of times in which he would be stopped

In this case we only need to multiply the probability by the number of times in which he passes an intersection and that would be 2/5 * 40 = 16 times

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)

answer: 40392

step-by-step explanation:

10098 x 4 = 40392