An electronics retailer offers an optional protection plan for a mobile phone it sells. Customers can choose to buy the protection plan for $100, and in case of an accident, the customer pays a $50 deductible and
the retailer will cover the rest of the cost of that repair. The typical cost to the retailer is $200 per repair,
and the plan covers a maximum of 3 repairs.
Let X be the number of repairs a randomly chosen customer uses under the protection plan, and let F be
the retailer's profit from one of these protection plans. Based on data from all of its customers, here are the
probability distributions of X and F:

$79

Step-by-step explanation:

That's the Khan Academy answer

79$ / 0.14

Step-by-step explanation:

Depending on the khan academy question the answer may differ between the two. Make sure to read your example closely. If it asks for dollars 79 is your answer if not go for 0.14. <3

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1

answer: 7

step-by-step explanation: