The perimeter of a rectangular parking lot is 296 m if the width of the parking lot is 65 m , what is its length

166

Step-by-step explanation:

So the width is 65, so two sides are each 65m long. So multiply 65*2 which is 130. this means that the other two sides need to equal 130 when added, so divide 130/2 which is 65

perimeter(p)=2(l+b)

2(l+b)=296

where b = 65

2(l+65)=296

2l+130=296

2l=296_130

2l=166

l=166÷2

l= 83

c.

step-by-step explanation:

substitution for (0,1)

y=x^2+4x+1

1=0^2+4(x)0+1

1=0+4(x)0+1

1=4(x)0+1

1=0+1

1=1

substitution for (-3,-2)

y=x+1

-2=-3+1

-2=-2