Help please please

1)  3x+4y=8

4y=-3x+8

4y/4=-3x/4+8/4

y=-3/4x+2

slope=-3/4

Y intercept=2

2) 9x+35=-5y

-5y/-5=9x/-5+35/-5

y=-9/5x-7

slope=-9/5

y intercept=-7

3)2y-6=-6x

2y−6+6=−6x+6

2y /2−6x/2+6 /2

y=−3x+3

slope is -3x

y intercept is 3

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation: