Lim t ->0 (tan (1+c)-tan(1) )/t when g(t)=t^2-5 table

if{t=1}

if{t=0.1}

if{t=0.01}

if{t=0.001}

if{t=0.0001}

if{t=0.00001}

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb

26?

step-by-step explanation:

step-by-step explanation:

to find if any function is an inverse of the other, put the first equation in as x in the next one. then simplify and solve. if at the end you get the statement y = x, then it is an inverse. if you get anything else, it is not.

include a picture of the drawing in order for me to

step-by-step explanation: