Mathematics, 28.01.2021 20:30 shyann78

A figure is dilated by a scale factor of 1/2. If the origin is the center of dilaton, what is the image of a vertex located at (3, 4)?

Answers: 2

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Answer from: measheaj

(9,12).

Step-by-step explanation:

If a figure dilated by a scale factor of k and origin is the center of dilation, then the relation between point and its image is defined asnIt is given that a figure is dilated by a scale factor of 3 and origin is the center of dilation. So, We need to find the image of a vertex located at (3, 4). So, substitute x=3 and y=4 in the above rule of dilation. Therefore, the image of a vertex located at (3, 4) is (9,12).

Answer from: yayrocks2395

(9,12).
Step-by-step explanation:
If a figure dilated by a scale factor of k and origin is the center of dilation, then the relation between point and its image is defined as

It is given that a figure is dilated by a scale factor of 3 and origin is the center of dilation. So,

We need to find the image of a vertex located at (3, 4). So, substitute x=3 and y=4 in the above rule of dilation.

Therefore, the image of a vertex located at (3, 4) is (9,12).

Answer from: Quest

$655.61 which is option c

step-by-step explanation:

price of house = $146,000

initial rate = 3.5%

mortgaged paid in this = 3.5 % of $146,000

= $\frac{3.5*146000}{100}$

=$5110

the total years would be = 7

total mortgaged paid = 7 * $5110

=$35770

remaining money = $146000-35770

=$110230

new mortgaged payment = 5 % of 110230

= $\frac{5*110230}{100}$

=$655.61

Answer from: Quest

correct choice is a

step-by-step explanation:

the equation of the line passing through the points $(x_1,y_1)$ and $(x_2,y_2)$ is

$\dfrac{x-x_1}{x_2-x_1}=\dfrac{y-y_1}{y_2-y_1}.$

thus, the equation of the line that passes through the points (0, -6) and (-3, 0) is

$\dfrac{x-0}{-3-0}=\dfrac{)}{)},\\ \\\dfrac{x}{-3}=\dfrac{y+6}{6},\\ \\2x=-y-6,\\ \\2x+y+6=0,\\ \\y=-2x-6.$

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A figure is dilated by a scale factor of 1/2. If the origin is the center of dilaton, what is the im...