Quadrilateral STUV with vertices S(−5, −2), T(−4, 7), U(0, 5), and V(3, −6) is dilated by a scale factor of 53. Which statement is false?

A Quadrilateral STUV is larger than quadrilateral S′T′U′V′.
A , Quadrilateral , STUV , is , larger, than quadrilateral , S′T′U′V′, .

C The algebraic representation of the dilation is (x, y)→(53x,53y)C , The algebraic representation of the dilation is open paren x comma y close paren rightarrow open paren 5 thirds x comma 5 thirds y close paren

D Quadrilateral STUV is smaller than quadrilateral S′T′U′V′

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation:

the answer would be 484

step-by-step explanation:

just multiply 0.484 times 1,000 (formula)

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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