Find an equation for a line with slope of
,passing through (2,-3)

Step-by-step explanation:

The point-slope form of the equation of a line: y - y₁ = m(x - x₁), where m is the slope and (x₁, y₁) is the point the line passing through.

m = ³/₄

(2, -3)    ⇒    x₁ = 2,  y₁ = -3

So the point-slope form of the equation:

                                                                   y - (-3) =³/₄(x - 2)      

                                                          or:   y + 3 = ³/₄(x - 2)

y + 3 = ³/₄x - ³/₂      {subtract 3 from both sides}

y = ³/₄x - ³/₂ - ⁶/₂

y = ³/₄x - ⁹/₂

-4

step-by-step explanation:

do 6-10=

if u need it to be negative.