The dot plots below show the distances traveled by two groups of cyclists: Two dot plots are labeled Group A and Group B. The horizontal axis is labeled Distance Traveled and marked from 15 to 40 at increments of 5 for both dot plots. Group A shows 3 dots on 20, 6 dots on 25, 7 dots on 30, 4 dots on 35, and 3 dots at 40. Group B shows 6 dots on 15, 8 dots on 20, 4 dots on 30, 3 dots on 35, and 2 dots on 40. Which of the following inferences can be made using the dot plots? The range of each group is the same. There is no overlap between the data. Group A has a higher mean than group B. Group B has a higher mean than group A.

for this pair of functions g(x)=x-2 and f(x)=|x| is (g o f)(a)= |a| -2

step-by-step explanation:

g(x)=x-2

f(x)=|x|

(g o f)(a)=?

(g o f)(x)=g(f(x))

(g o f)(x)=g(|x|)

(g o f)(x)=|x|-2

(g o f)(a)=|a|-2

k

step-by-step explanation:

domit

asnwer is (g o h o f)(x) = 2x - 6/x + 7

step-by-step explanation:

given,

f(x) = x - 3/x

g(x) = x + 3

h(x) = 2x + 1

we need to find : (g o h o f)(x)

we can write (g o h o f)(x) = g[ h{ f(x) } ]

so first we find h{f(x)}

h{f(x)} = f(x) + 3 = (x - 3/x) + 3

h{f(x)} = x - 3/x + 3

now we find g[ h{ f(x) } ].

g[ h{ f(x) } ] = g(x - 3/x + 3)       {plug h{f(x)} = x - 3/x + 3 in g[h{f(x)}] }

g(x - 3/x + 3) = 2 (x - 3/x + 3) + 1

                    = 2x - 6/x + 6 + 1

                    = 2x - 6/x + 7

hence we get (g o h o f)(x) = 2x - 6/x + 7