Tom walked at a consistent pace from the economy parking garage to the airport terminal. he stood on a a moving sidewalk for 2/5 of the route, moving at twice his normal walking pace. he made the trip in 6 minutes. on his return trip, the moving sidewalk was out of order, so how long did it take him to walk back?

Let x be the number of minutes for his normal walk

On the way to the airport, for the 2/5 (or 40%) of his route, his speed is twice faster. Hence, the number of x should be divided to 2. The rest of the route (60%) was on his normal pace. The total minutes is 6. The equation is:

0.4(x÷2) + 0.6x = 6

Solving for x, the number of minutes for his normal walk is 7.5 minutes.

10.416 meters per second

step-by-step explanation:

distance=1 00 meters

time= 9.6 seconds in decimal form or 9 3/5 as a mixed number

average speed= 100/9.6

=10.416 meters per second or 10 52/125 as a mixed number.