The angle bisectors of A EFG are ES, FS, and GS. They meet at a single point S. (In other words, S is the incenter of A EFG.)
Suppose PS= 14, ES=19, mZPER=949, and mZRGS=16º.
Find the following measures.
Note that the figure is not drawn to scale.
F
m ZRGQ=
- 0
DO
m ZOFS =
$
00
1
S
QS =
E
R

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option

what graph

step-by-step explanation:

i think it might be a but you might want a second opinion

it would rotate about 180 degrees.