Question 4 of 10 What is the distance between the points (3, 7) and (15, 16) on a coordinate
plane?

15

Step-by-step explanation:

distance = Sqrt((x2-x1)^2 +(y2-y1)^2)

15-3 =12

16-7=9

12^2 = 144

9^2 = 81

144+81 = 225

square root of 225 = 15

the distance is 15

395.84

step-by-step explanation:

2πrh+2πr²

2 (pie)(radius)(height)+2(pie)(radius)^2

y-y1=4(x-x1)

step-by-step explanation:

this is point-slope form since you only have 4 as the slope it goes in place of m

hope this : )