Enormous State University's Math Department offers two courses: Finite Math and Applied Calculus. Each section of Finite Math has 60 students, and each section of Applied Calculus has 50 students. The department will offer a total of 110 sections in a semester, and 6,000 students would like to take a math course. How many sections of each course should the department offer in order to fill all sections and accommodate all of the students

the department should offer 50 sections of finite math and 60 section of applied calculus in order to fill all sections and accommodate all of the students

Step-by-step explanation:

Given the data in the question'

let x represent number of sections of finite math while y represent number of section of applied calculus.

as 6000 student will like to take math course;

in each section, finite math has 60 students while applied calculus has 50 students

so;

60x + 50y = 6000 lets this be equ 1

we also know that; there are 110 sections in a semester

so;

x + y = 110 let this be equ 2

multiply equation 2 by ( - 60 )

-60x + -60y = -6600 let this be equ 3

now lets add equation 1 and 3

0 - 10y = -600

-10y = -600

divide both sides by (-10)

-10y/-10 = -600/-10

y = 60

now lets substitute value of y in equation 2

x + 60 = 110

x = 110 - 60

x = 50

Therefore, the department should offer 50 sections of finite math and 60 section of applied calculus in order to fill all sections and accommodate all of the students

the answer would be c:   ax + b = ax + c

step-by-step explanation: