Find the asymptotes of the following functions

a) y = -6/x has a vertical asymptote at x = 0

b) y = 1/(2·x) - 1 has two asymptotes;

1) A vertical asymptote at x = 0

2) A horizontal asymptote at y = -1

Step-by-step explanation:

The asymptote is given as the line in which the distance between the graph and the line draws closer to zero as either the 'x', or 'y', or both 'x', and 'y', approaches infinity

a) The given equation is y = -6/x

Therefore, the function does not have a horizontal or oblique asymptote only a vertical asymptote at x = 0

b) The given equation is y = 1/(2·x) - 1

∴ y = (1 - 2·x)/(2·x)

The function has a vertical asymptote at x = 0

The function has an horizontal asymptote at y = -2/2 = -1

its 4 because 2 times 2 is 4, if you double the number two you get four