Mathematics, 29.01.2021 16:20 brook633
Fill in the blanks to solve 102\times4102×4102, times, 4. \phantom{=}\blueD{102}\times\greenD 4=102×4empty space, start color #11accd, 102, end color #11accd, times, start color #1fab54, 4, end color #1fab54 =(\blueD{100} ~+~ \=(100 + equals, left parenthesis, start color #11accd, 100, end color #11accd, space, plus, space, space ) \times \greenD4)×4right parenthesis, times, start color #1fab54, 4, end color #1fab54 =(\blueD{100}\times\greenD4) + (=(100×4)+(equals, left parenthesis, start color #11accd, 100, end color #11accd, times, start color #1fab54, 4, end color #1fab54, right parenthesis, plus, left parenthesis {}\times\greenD4)×4)times, start color #1fab54, 4, end color #1fab54, right parenthesis =400 ~+ \=400 + equals, 400, space, plus, space ==equals
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Fill in the blanks to solve 102\times4102×4102, times, 4. \phantom{=}\blueD{102}\times\greenD 4=102×...
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