Write the linear equations in slope-intercept form with a slope of 5 and point (2, -20)

We conclude that the linear equation in slope-intercept form with a slope of 5 and point (2, -20) is:

Step-by-step explanation:

The slope-intercept form of the line equation

where

Given

The slope m = 5

The point (2, -20)

now substitute (x, y) = (2, -20) and m = 5 in the slope-intercept form of the line equation

y = mx+b

-20 = 5(2) + b

10 + b = -20

subtracting 10 from both sides

10 + b - 10 = -20 - 10

b = -30

Thus, the y-intercept b = -30

so substituting b = -30 and m = 5 in the slope-intercept form of the line equation

y = mx+b

y = 5x + (-30)

y = 5x - 30

Therefore, the linear equation in slope-intercept form with a slope of 5 and point (2, -20) is:

1.3

step-by-step explanation:

3x2=6   9x+6

bring down the 6 on both sides

6+6=12

12= 9x

divide by 9

12/9 =

1.3 =x

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.