Figure D is a regular polygon. If D’ is a 20 degree rotation of D and is concurrent to D, what is the smallest number of sides that D could have?

18

Step-by-step explanation:

I've never heard of concurrent polygons. I'm assuming that by rotating D by 20°, D keeps its original orientation. Therefore, an exterior angle of D is 20°.

number of sides = 360°/20° = 18

if you explain the the question more correctly i might be able to answer this better

step-by-step explanation:

ab will be equal to