harmony places the letters of December into a bag. a letter will be randomly selected and not replaced. then the other letter will be selected. what is the probability of harmony selecting a C and then E?

1/56

Total letters are 8

probability of first selecting c is 1/8 and since it's not replaced, probability of selecting e is 1/7

Total probability= 1/8*1/7=1/56

Therefore, total probability is 1/56

Step-by-step explanation:

answer is x<

yes the total will be same because in both of them the expression.is rearranged but their sign remains the same hence it hss just been shuffled