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Mathematics, 30.01.2021 01:00 skykopystecky795

PLZ GUYS IM BEGGING U JUST ASWER THE ONES YOU KNOW AND ILLL GIVE BRAINLIEST PL ALSO 20 POINTSS Question 6(Multiple Choice Worth 1 points)
(04.02 MC)

A contractor is building a new subdivision on the outside of a city. He has started work on the first street and is planning for the other streets to run in a direction parallel to the first. The second street will pass through (βˆ’5, βˆ’1). Find the equation of the location of the second street in standard form.

coordinate grid with a segment labeled Street 1 that extends between the points negative 5 comma 6 and three comma negative 2; a point labeled Street 2 is at negative 5 comma negative 1

x βˆ’ y = βˆ’6
2x + y = βˆ’11
x + y = βˆ’6
2x βˆ’ y = βˆ’9
Question 7(Multiple Choice Worth 1 points)
(04.02 HC)

Which statement explains the relationship of sides BA and B'A' after rectangle BADC has been rotated 180Β° about the origin?

coordinate plane with rectangle ABCD at A 3 comma 5, B 1 comma 3, C 5 comma negative 1, and D 7 comma 1

Side B'A' has a slope of βˆ’1 and is perpendicular to side BA.
Side B'A' has a slope of 1 and is parallel to side BA.
Side B'A' has a slope of 1 and is perpendicular to side BA.
Side B'A' has a slope of βˆ’1 and is parallel to side BA.
Question 8(Multiple Choice Worth 1 points)
(04.02 MC)

The equation of line WX is 2x + y = βˆ’5. What is the equation of a line perpendicular to line WX in slope-intercept form that contains point (βˆ’1, βˆ’2)?

y = one half x + three halves
y = negative one halfx + three halves
y = one half x βˆ’ three halves
y = negative one halfx βˆ’ three halves
Question 9(Multiple Choice Worth 1 points)
(04.02 MC)

Square EFGH is drawn on a coordinate plane. Side FE is on the line y βˆ’ 2 = βˆ’2(x + 6). What is the slope of the side FG?

negative one half
one half
βˆ’2
2
Question 10(Multiple Choice Worth 1 points)
(04.02 LC)

The equation of line EF is y = negative one halfx + 6. What is the equation of a line parallel to line EF in slope-intercept form that contains point (0, βˆ’2)?

y = βˆ’2x βˆ’ 2
y = negative one halfx + 2
y = negative one halfx βˆ’ 2
y = βˆ’2x + 2

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