The function P(t)=87,000e^0.106t models the population of a city, t years after 2010. How many people lived in the city in 2010? At what rate is the population change in? Explain

87,000 ; 10.6%

Step-by-step explanation:

Given the function :

P(t)=87,000e^0.106t

P(t) is an exponential function ; comparing the given function to the general form of an exponential function :

y = Ae^rt

Where,

A = initial amount ; r = growth rate ; t = time

The Given function models t years after 2010, that is the 2010 population is the initial population of the city.

Comparing the general exponential equation with the function given:

A = 87,000 = population of city in 2010

The growth rate :

rt from the general equation compares to 0.106t in the given function.

rt = 0.106t

r = 0.106

Hence, the rate of change = 0.106 * 100% = 10.6%

l.jnl.j/n.m,lm,

step-by-step explanation:

rick has $1400 and sally has $1500

step-by-step explanation:

to find amount of money rick has after 10 years :

principal = $1000 , time = 10 years , rate = 4% annually

to find amount of money sally has after 10 years :

her friend gives to pay her $50 per year, therefore money she has after 10 years = 50 × 10 = $500

also, sally gets $1000 after 10 years,

therefore, total amount of money sally has after 10 years = 500 + 1000 = $1500

so, after 10 years : rick has $1400 and sally has $1500