What is the sum of all of the single-digit positive whole numbers that evenly divide 72?

33

Step-by-step explanation:

So all the single-digit positive whole numbers that evenly divide 72 would be:

1 (72 / 1 = 72)

2 (72 / 2 = 36)

3 (72 / 3 = 24)

4 (72 / 4 = 18)

6 (72 / 6 = 12)

8 (72 / 8 = 9)

9 (72 / 9 = 8)

Then, 1 + 2 + 3 + 4 + 6 + 8 + 9 = 3 + 7 + 14 + 9 = 10 + 23 = 33

the answer is -6

step-by-step explanation:

the answer is -6 because its next to the variable m