Miles has a train collection with 36 engines, 72 boxcars, and 18 cabooses. He wants to arrange the train cars in equal rows with only one type of train car in each row. How many can he put in each row? Mark 4 that apply.

Kindly check explanation

Step-by-step explanation:

Given that:

Number of engines = 36

Number of car boxes = 72

Number of cabooses = 18

To areange in equal rows :

We need to obtain the greatest common factor :

Factors of :

36 : 2, 3, 4, 6, 9, 12, 18, 36

18 : 2, 3, 6, 9, 18

72 : 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72

The greatest common factor (GCF) is 18

Number that can be put in each row :

Cabooses :

18 / GCF = 18 / 18 1 row

Engines :

36 / GCF = 36 /18 = 2 rows

Box cars :

72 / GCF = 72 / 18 = 4 rows

1/4 and 8/3 because:

the reciprocal if 4 is 1/4 because 4 is used as 4/1 and the opposite of that is 1/4. the opposite of 3/8 is 8/3 so that is the answer.

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 =

x = 3, y = 216 =

x = 4, y = 1296 =

x = 5, y = 7776 =

so, the geometric series obtained is .

thus, the common ratio is given by = = 6.

hence, the common ratio is 6.