If XY = 48. XZ = 36, JQ = 7, and the radius of the circumscribed circle of AXYZ is 25, find QK.

17.3

Step-by-step explanation:

I had a test and this is what they had as the answer.

i hope this is what you were looking for.

see attached graph

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92