Please solve for me it's urgent. A rectangle has 10 and 6cm each. find the area of a square with the same perimeter as that of the rectangle

64 cm²

Step-by-step explanation:

Firstly,let us lay down the clues;

So, we have been given the Length and Width of the rectangle.

Rectangle;

Length= 10 cm

Width=6 cm

We know that

Perimeter= 2L + 2W

Perimeter= 10+10+6+6

Perimeter =32 cm

In the questionnaire, it is mentioned that a square has the same perimeter as the rectangle. That means, the perimeter of the square is similar to the one of the rectangle which is 32 cm.

So,

Perimeter of square =32 cm

Length of one side of the square =32÷4

=8 cm

Area= L × W

Area= 8 cm× 8 cm

Area= 64 cm²

Hope it helps.

y=−9/2x+10

step-by-step explanation:

let's solve for y.

0−9x−2y=−20

step 1: add 9x to both sides.

−9x−2y+9x=−20+9x

−2y=9x−20

step 2: divide both sides by -2.

−2y

−2

=

9x−20

−2

y=

−9

2

x+10

26

step-by-step explanation: