4. 8 16,
Find the next 3 term of geometric sequence

32, 64, 128

Step-by-step explanation:

Let us start by looking at the geometric progression. A geometric progression multiplies each number by a constant, which we can name r, to get the next term. Let us find this constant:

16÷8=2

8÷4=2

Both expressions confirm that our r, the constant, is indeed 2.

To find the next few terms, we simply multiply by r:

1. 16r=16×2=32

2. 32r=32×2= 64

3. 64r= 64×2 = 128

I hope this helps! Please let me know if you have any further questions :)

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