Find three consecutive integers whose sum is −96.

The first consecutive integer = - 33

The second consecutive integer = - 32

The third consecutive integer = - 31

Step-by-step explanation:

So since the three numbers are consecutive we can make the following equation. If we let "n: be the value of the first consecutive integer, the value of the second consecutive integer would be "n + 1" and the value of the third one would be "n + 2". So the equation we can write is...

n + (n + 1) + (n + 2) = - 96

3n + 3 = - 96

3n = - 99

n = - 33

Therefor:

The first consecutive integer = n = - 33

The second consecutive integer = n + 1 = - 33 + 1 = - 32

The third consecutive integer = n + 2 = - 33 + 2 = - 31

-1, -2, -3, -4, -6

step-by-step explanation:

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 =

x = 3, y = 216 =

x = 4, y = 1296 =

x = 5, y = 7776 =

so, the geometric series obtained is .

thus, the common ratio is given by = = 6.

hence, the common ratio is 6.